A metal complex of coordination number six ha | vedclass

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Question

(B) For a coordination complex of the type $Ma_2b_2c_2$ with coordination number $6$,the geometrical isomers are determined by the relative positions

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) For a coordination complex of the type $Ma_2b_2c_2$ with coordination number $6$,the geometrical isomers are determined by the relative positions of the ligands.There are $5$ possible geometrical isomers for this composition:$1$. All pairs of identical ligands are trans to each other (all-trans).$2$. Two pairs are trans and one pair is cis.$3$. One pair is trans and two pairs are cis.$4$. All pairs are cis to each other (two distinct arrangements).Thus,the total number of geometrical isomers is $5$.

$A$ metal complex of coordination number six having three different types of ligands $a$,$b$ and $c$ of composition $Ma_2b_2c_2$ can exist in several geometrical isomeric forms; the total number of such isomers is

Similar Questions

Consider the complexes:
$I$. $[Pd(NH_3)_2 ClBr]$
$II$. $[Pd(NH_3)_2 Cl_2]$
$III$. $[Pd(en) Cl_2]$
$IV$. $[Pd(en) ClBr]$
$V$. $[Pd(en)_2 Cl_2]$
(en = ethylenediamine)
The total number of geometrical isomers of $(I)$ is the same as the total number of geometrical isomers of:

The magnetic moment of $Fe^{2+}$ is $B.M$.

Which of the following compounds is colored but does not contain any unpaired electrons?

Total number of unpaired electrons present in the central metal atoms/ions of $[Ni(CO)_{4}]$, $[NiCl_{4}]^{2-}$, $[PtCl_{2}(NH_{3})_{2}]$, $[Ni(CN)_{4}]^{2-}$ and $[Pt(CN)_{4}]^{2-}$ is . . . . . . .

The complex with a maximum number of stereoisomers is

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